The basic **hyperboloid of one sheet** is given by the equation
$$\frac{x^2}{A^2}+\frac{y^2}{B^2} - \frac{z^2}{C^2} = 1$$
The hyperboloid of one sheet is possibly the most complicated of
all the quadric surfaces. For one thing, its equation is very
similar to that of a hyperboloid of two sheets, which is confusing.
(See the section on the two-sheeted hyperboloid for some tips on
telling them apart.) For another, its cross sections are quite
complex.

Having said all that, this is a shape familiar to any fan of the Simpsons, or even anybody who has only seen the beginning of the show. A hyperboloid of one sheet looks an awful lot like a cooling tower at the Springfield Nuclear Power Plant.

Below you can see the cross sections of a simple
one-sheeted hyperboloid with \(A=B=C=1\). The horizontal cross
sections are ellipses — circles, even, in this case — while the
vertical cross sections are hyperbolas. The reason I said they are
so complex is that these hyperbolas can open up and down *or*
sideways, depending on what values you choose for \(x\) and
\(y\). Check the example and see for yourself. Yikes! If you
do these cross sections by hand, you have to check an awful lot of
special cases.

The constants \(A\), \(B\), and \(C\) once again affect how much the hyperboloid stretches in the \(x\)-, \(y\)-, and \(z\)-directions. You can see this for yourself in the second picture, which shows the portion of the hyperboloid between the planes \(z=-3\) and \(z=3\).

One caveat: the picture only shows a small portion of the hyperboloid, but it continues on forever in the vertical direction. If you know something about partial derivatives, you could investigate how quickly \(z\) changes with respect to \(x\) and \(y\) for different values of \(C\). You could also explore why adjusting \(C\) seems to have a more dramatic effect than changing \(A\) and \(B\).

Here are a few more points for you to consider.

- Once again, the sliders don’t go all the way to 0. Why not? Make all of them as small as possible and zoom in to see the resulting hyperboloid. What other quadric surface does the picture resemble?
- Look at the equation. What should happen for the slices \(x=A\) or \(x=-A\)? Check this in the first picture; recall that \(A=1\) there.
- Does there always have to be a "hole" through the hyperboloid, or could the sides touch at the origin? In other words, could the cross section given by \(z=0\) ever be a point instead of an ellipse? Experiment with the second picture; be sure to look directly from the top and zoom in before just assuming that the hole is gone.